10x^2+80x+158=0

Solution for 10x^2+80x+158=0 equation:

10x^2+80x+158=0

a = 10; b = 80; c = +158;
Δ = b2-4ac
Δ = 802-4·10·158
Δ = 80
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{80}=\sqrt{16*5}=\sqrt{16}*\sqrt{5}=4\sqrt{5}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-4\sqrt{5}}{2*10}=\frac{-80-4\sqrt{5}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+4\sqrt{5}}{2*10}=\frac{-80+4\sqrt{5}}{20}
$